Count Servers that Communicate

class Solution {
public:
    int serverCounter(vector<vector<int>>& matrix) {
        int row = matrix.size(), col = matrix[0].size();
        int countCommServers = 0;

        for (int i = 0; i < row; ++i) {
            int serverCount in Row = 0;
            int firstServerCol = -1;

            // Finding servers in the current row
            for (int j = 0; j < col; ++j) {
                if (matrix[i][j]) {
                    if (serverCountInRow == 0) {
                        firstServerCol = j;
                    }
                    serverCountInRow += 1;
                }
            }

            // Determine if servers in this row can communicate
            bool canTalk = (serverCountInRow > 1);

            // Checking for communication possibility for a lonely server
            if (!canTalk) {
                for (int k = 0; k < row; ++k) {
                    if (k != i && matrix[k][firstServerCol]) {
                        canTalk = true;
                        break;
                    }
                }
            }

            // Add to total if communication is possible
            if (canTalk) {
                countCommServers += serverCountInRow;
            }
        }

        return countCommServers;
    }
};

The provided C++ solution addresses the problem of counting servers that can communicate in a grid. The grid is represented as a 2D vector where each element can be either 0 (no server) or 1 (server present). The function serverCounter expects this grid as input and returns the number of servers that are able to communicate.

Here's a breakdown of the steps involved in the implementation:

• Initialize variables:

  • row and col are initialized to store the dimensions of the matrix.
  • countCommServers is initialized to keep track of the count of communicating servers.

• Iterate through each row of the matrix:

  • For each row, maintain a count of servers (serverCountInRow) and the column index of the first server found (firstServerCol).

• Check within row:

  • Traverse each column in the current row to count how many servers are present and note the position of the first server.

• Assess communication ability:

  • After counting, determine if servers within the same row can communicate based on whether there are more than one server in that row (serverCountInRow > 1).
  • If a single server is found in a row, check other rows to see if there's another server in the same column, allowing cross-row communication.

• Update communicating servers count:

  • If communication is established either within the same row or across rows, add the count of servers in that row to countCommServers.

• Return result:

  • Finally, the function returns the count of servers that can communicate.

This solution effectively uses nested loops and a logical determination of communication paths to solve the problem efficiently within the constraints of the grid matrix.

class Solution {

    public int calculateCommunicatingServers(int[][] networkGrid) {
        int totalRows = networkGrid.length, totalColumns = networkGrid[0].length;
        int countOfCommunicableServers = 0;

        for (int row = 0; row < totalRows; ++row) {
            int numServersInRow = 0;
            int lastFoundServerColumn = -1;

            // Count servers in this row and note the column of the first server found
            for (int col = 0; col < totalColumns; ++col) {
                if (networkGrid[row][col] == 1) {
                    if (numServersInRow == 0) {
                        lastFoundServerColumn = col;
                    }
                    numServersInRow++;
                }
            }

            // Determine if the current row of servers can communicate
            boolean isCommunicableRow = (numServersInRow != 1);

            // If row has one server, check other rows for any server in the same column
            if (!isCommunicableRow) {
                for (int otherRow = 0; otherRow < totalRows; ++otherRow) {
                    if (otherRow != row && networkGrid[otherRow][lastFoundServerColumn] == 1) {
                        isCommunicableRow = true;
                        break;
                    }
                }
            }

            // Add to communicable servers if this row's servers can communicate
            if (isCommunicableRow) {
                countOfCommunicableServers += numServersInRow;
            }
        }

        return countOfCommunicableServers;
    }
}

This Java solution tackles the problem of identifying servers that can communicate in a grid (represented as a 2D array) where each cell with a value of 1 represents a server.

• The method calculateCommunicatingServers receives a 2D integer array named networkGrid as input.
• Two integer variables, totalRows and totalColumns, store the total number of rows and columns in networkGrid respectively.
• Another integer, countOfCommunicableServers, initiated to zero, is used to keep track of the total number of servers that can communicate.
• The solution iterates over each row and determines how many servers (numServersInRow) it contains and records the column index of the last found server (lastFoundServerColumn).
• A server is considered communicable if it shares its row or its column with at least one other server.
• For each row:
  • If only one server is found in that row, the code further checks other rows to determine if any server resides in the same column (lastFoundServerColumn).
  • If communicability condition is satisfied either through row or column sharing, the number of servers in that row is added to countOfCommunicableServers.
• Finally, the method returns the total count of servers that can communicate.

This approach efficiently captures the communicability of servers by exploiting grid traversal and condition checks to ensure that every server that can communicate is counted accurately.

class Solution:
    def calculateCommServers(self, grid: List[List[int]]) -> int:
        row_count = len(grid)
        col_count = len(grid[0])
        comm_servers = 0

        for row_index in range(row_count):
            num_servers = 0
            col_track = -1

            # Find servers in the current row and track the first server's index
            for col_index in range(col_count):
                if grid[row_index][col_index] == 1:
                    if num_servers == 0:
                        col_track = col_index
                    num_servers += 1

            # Determine if servers in this row can communicate
            communicates = (num_servers != 1)

            # Check for communication from other rows in the same column
            if not communicates:
                for i in range(row_count):
                    if i != row_index and grid[i][col_track] == 1:
                        communicates = True
                        break

            # Increment count based on communication ability
            if communicates:
                comm_servers += num_servers

        return comm_servers

The given Python program defines a method to count the number of servers that can communicate among themselves within a same row or column of a grid. The grid is represented by a 2D list, where 1 represents a server and 0 represents an empty space.

Here's a breakdown of the solution's approach:

1. Initialize counter variables for the number of rows and columns, as well as for the total communicating servers.

2. Iterate through each row. For each row:

   • Initialize an internal counter to track the number of servers in that row and a variable to keep a reference to the first server's column index (if any).
   • Traverse through the columns of that row to count servers and record the index of the first server found.

3. After counting, check if there is more than one server in the current row. This indicates potential communication within the row.

4. If only one server is found in a row, check other rows for a server in the same column—this establishes vertical communication possibilities.

5. If communication (either horizontal within the row, or vertical across rows from the same column) is verified, add the number of servers in the current row to the total count of communicating servers.

6. Return the count of communicating servers.

This solution efficiently checks each server's communication ability by only considering relevant rows and columns and increases the counter upon confirming communication capability. This minimizes unnecessary computations and enhances performance, especially for larger grids.