
In this task, you are given an array of direct paths represented as pairs, where each pair [cityAi, cityBi] indicates a direct route from cityAi to cityBi. Your goal is to determine which city is the ultimate destination of this sequence of trips. The destination city is identified as the one which does not have any other city listed as its destination in the provided array of paths. Essentially, you have to find a city from which no outgoing paths are present in the given list. This problem is set in a graph context without loops, ensuring a straightforward path leading to a unique endpoint city.
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1 <= paths.length <= 100paths[i].length == 21 <= cityAi.length, cityBi.length <= 10cityAi != cityBiTo find the destination city, consider the following approach:
cityAi) and all cities that are endpoints (cityBi) in separate lists or sets.Example Analyses from Provided Examples:
Example 1:
[["London","New York"],["New York","Lima"],["Lima","Sao Paulo"]]London, New York, LimaNew York, Lima, Sao PauloSao Paulo is the only city among end cities that does not appear as a start city, hence it is the destination.Example 2:
[["B","C"],["D","B"],["C","A"]]B, D, CC, B, AA appears solely in the endpoint list, making it the destination.Example 3:
[["A","Z"]]AZZ does not appear as a start city, therefore it's identified as the destination.This approach systematically processes the paths to single out the destination city based on the properties of the graph formed by the paths.
This solution involves finding the destination city from a given list of routes. Each route is represented as a vector of strings, where the first string is the departure city and the second is the destination city. The solution utilizes C++ and the standard library's unordered_set to efficiently determine the unique destination city that does not act as a departure city for any other route.
Solution with a public member function string findDestinationCity(vector<vector<string>>& routes).citiesWithDeparture to store cities that are departure points.citiesWithDeparture set with the first city of each route (departure city).citiesWithDeparture set.citiesWithDeparture, return this city as it does not serve as a departure city and thus, is the final destination.This method ensures an efficient check by taking advantage of the fast look-up times of unordered sets, concluding with a solution that meets the problem's requirements.
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