
Alice has a collection of n candies, each identified by a type candyType[i]. Due to health concerns, specifically weight gain, her doctor has advised her to limit her consumption to half of her candies, where n is always an even number. Given her love for variety, Alice would like to maximize the number of different candy types she can enjoy within this limit. The task is to determine the maximum variety of candies Alice can consume, where she is only allowed to eat n / 2 candies out of her total collection.
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n == candyType.length2 <= n <= 104n is even.-105 <= candyType[i] <= 105To solve this problem, we need to consider the following points:
Calculate half of the total number of candies: allowed = n / 2. This represents the maximum number of candies Alice is allowed to eat according to the doctor's advice.
Determine the number of unique candy types available in the candyType array using a data structure like a set to filter out duplicates.
Compare the number of unique candy types with allowed.
allowed, then Alice can consume candies of allowed different types.allowed, then Alice's variety is limited to the number of unique types available.Let's go through the examples to clarify these steps:
For candyType = [1,1,2,2,3,3]:
For candyType = [1,1,2,3]:
For candyType = [6,6,6,6]:
From these observations and the problem's constraints, we can model our solution to first count the unique candy types, then simply return the minimum of allowed and the count of unique types to get the maximum variety of candies Alice can eat.
The provided Java solution focuses on determining the maximum number of different types of candies one can have from an array where each integer represents a type of candy. Firstly, the solution utilizes a HashSet to record unique candy types from the input array. Since a HashSet does not allow duplicate entries, it automatically retains only unique candy types.
The key part of the solution lies in the calculation:
Math.min(candySet.size(), candies.length / 2) This line determines the maximum number of types a person can have by choosing the lesser value between the unique types available (candySet.size()) and half of the total number of candies (candies.length / 2). The division by two enforces a constraint where at most half of the candies can be chosen. This approach ensures that the selection of candies meets the requirement of both maximizing the variety and abiding by the allowed quantity.In summary, the solution efficiently calculates the maximum number of different candy types one can possess by evaluating the smaller between the number of unique candy types and half the total number of candies given.
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