
Problem Statement
We need to work with a "circular" array where indexing beyond its bounds leads back to the start (or the end, if going in reverse). Given an initial array arr
and a starting index startIndex
, create a generator gen
. The behavior of this generator is defined by the following steps:
- The generator first yields the element at
startIndex
inarr
whengen.next()
is invoked without any arguments. - For subsequent calls to
gen.next(jump)
, the generator calculates a new index by adding or subtractingjump
to the previous index:- If
jump
is positive and stepping over the array's end, the index loops to the beginning of the array. - If
jump
is negative and stepping before the array's start, the index loops to the end of the array.
- If
- The generator should yield the value of
arr
at the new index after each call.
This task challenges our understanding of both generators in programming and manipulating indices in a cyclic manner, useful for scenarios like buffer cycling, round-robin scheduling, etc.
Examples
Example 1
Input:
arr = [1,2,3,4,5], steps = [1,2,6], startIndex = 0
Output:
[1,2,4,5]
Explanation:
const gen = cycleGenerator(arr, startIndex); gen.next().value; // 1, index = startIndex = 0 gen.next(1).value; // 2, index = 1, 0 -> 1 gen.next(2).value; // 4, index = 3, 1 -> 2 -> 3 gen.next(6).value; // 5, index = 4, 3 -> 4 -> 0 -> 1 -> 2 -> 3 -> 4
Example 2
Input:
arr = [10,11,12,13,14,15], steps = [1,4,0,-1,-3], startIndex = 1
Output:
[11,12,10,10,15,12]
Explanation:
const gen = cycleGenerator(arr, startIndex); gen.next().value; // 11, index = 1 gen.next(1).value; // 12, index = 2 gen.next(4).value; // 10, index = 0 gen.next(0).value; // 10, index = 0 gen.next(-1).value; // 15, index = 5 gen.next(-3).value; // 12, index = 2
Example 3
Input:
arr = [2,4,6,7,8,10], steps = [-4,5,-3,10], startIndex = 3
Output:
[7,10,8,4,10]
Explanation:
const gen = cycleGenerator(arr, startIndex); gen.next().value // 7, index = 3 gen.next(-4).value // 10, index = 5 gen.next(5).value // 8, index = 4 gen.next(-3).value // 4, index = 1 gen.next(10).value // 10, index = 5
Constraints
1 <= arr.length <= 104
1 <= steps.length <= 100
-104 <= steps[i], arr[i] <= 104
0 <= startIndex < arr.length
Approach and Intuition
Initializing the Generator:
- Start by creating a generator function that takes
arr
andstartIndex
. - Initialize the current index to
startIndex
and yieldarr[startIndex]
right away on the first.next()
invocation.
- Start by creating a generator function that takes
Handling the Jump:
- Every subsequent
.next(jump)
call adjusts the current index. - Adjustments account for the circular nature:
- For positive
jump
:(current_index + jump) % len(arr)
- For negative
jump
:(current_index + jump) % len(arr)
ensures the value wraps around correctly even for negative jumps (e.g., -1 from 0 goes to the last index of the array).
- For positive
- Every subsequent
Yielding Values:
- Post jump adjustment, yield the value at the new index from
arr
. - The
%
operator is used for efficient wrap-around handling as it computes the remainder, making it apt for circular indexing—negative indices also loop back with this method correctly.
- Post jump adjustment, yield the value at the new index from
By understanding these operations, we can practically apply concepts like modulo for cyclic operations and generators for stateful iteration, which can be visualized with concrete examples. The dynamic manipulation of indices and the state retention between generator invocations makes this technique powerful for various applications in computing, such as stream processing or scheduling tasks in operating systems.
Solutions
- JavaScript
var rotateElements = function* (elements, initialIndex) {
while (true) {
const step = yield elements.at(initialIndex % elements.length);
initialIndex += step;
}
}
In this solution, the task is to generate circular array values using JavaScript. The provided code employs a generator function rotateElements
that iteratively yields the elements from a given array elements
, starting from a specified initialIndex
. The function ensures circular traversal using the modulo operator, which wraps the index around the array length.
Here's a breakdown of the process:
- Define the generator function
rotateElements
with parameterselements
(an array) andinitialIndex
(the starting index in the array). - Use an infinite
while
loop to ensure continuous iteration. - Use
yield
to return the current element of the array, wherein the index is computed asinitialIndex % elements.length
. This calculation helps in cycling back to the start of the array when the end is exceeded. - Update the
initialIndex
with the valuestep
provided when the generator function is resumed. This allows the position in the array from which to yield elements to be dynamically adjusted.
This approach ensures flexibility and efficiency in working with circular arrays, especially in scenarios where the traversal order and starting position might need to be changed dynamically. The use of generator function and modulo operator here is key to achieving the desired cyclic behavior.
No comments yet.