Largest Color Value in a Directed Graph

Updated on 03 June, 2025
Largest Color Value in a Directed Graph header image

Problem Statement

In this task, we have a directed graph consisting of n nodes each associated with a color and m directed edges connecting these nodes. Each node's color is represented by a lowercase English letter. The problem involves analyzing the graph to compute specific characteristics based on the paths from one node to another. A valid path in this context is defined as a sequence of nodes where each is directly connected to the next via a directed edge. The aim is to find the path that maximizes the count of the most frequently appearing color on that path. The result will be the highest count of a single color appearing in any valid path, known as the "largest color value". An additional complexity arises if the graph contains cycles (a sequence where a node can eventually reach itself through directed edges), in which case the output should be -1, indicating an unresolvable condition for achieving a maximal path due to the repetitive looping.

Examples

Example 1

Input:

colors = "abaca", edges = [[0,1],[0,2],[2,3],[3,4]]

Output:

3

Explanation:

The path 0 -> 2 -> 3 -> 4 contains 3 nodes that are colored `"a" (red in the above image)`.

Example 2

Input:

colors = "a", edges = [[0,0]]

Output:

-1

Explanation:

There is a cycle from 0 to 0.

Constraints

  • n == colors.length
  • m == edges.length
  • 1 <= n <= 105
  • 0 <= m <= 105
  • colors consists of lowercase English letters.
  • 0 <= aj, bj < n

Approach and Intuition

  1. Analysis of the problem reveals a need to scan possible paths for calculating frequency of colors.
  2. Since the graph is directed and may contain cycles, the detection of cycles is crucial because their presence nullifies the search for a path (returning -1 instead).
  3. Graph traversal techniques such as Depth-First Search (DFS) or Breadth-First Search (BFS) can be employed where, during traversal, you maintain a frequency count of colors observed along each path.
  4. To handle cycles, especially in large graphs (with n up to 10^5 nodes), we utilize additional data structures like a visited list or recursion stack to keep track of nodes currently in the traversal stack.
  5. For each path explored, update the maximum frequency of the most occurring color. This may be done using a map or direct array given the nodes are associated with colors through indices and colors are limited to lowercase English letters.
  6. At the end of traversal, the maximum frequency recorded across all paths will be the answer if no cycles are detected. If a cycle is detected in any of the paths, the requirement demands returning -1.

This combinatorial and graph theoretical approach, when paired with cycle detection mechanisms, will allow handling the constraints effectively and solve the problem within required limits.

Solutions

  • C++
  • Java
cpp
class Solution {
public:
    int explore(int vertex, string& nodeColors, vector<vector<int>>& graph, vector<vector<int>>& colorCount,
                vector<bool>& visited, vector<bool>& recursionStack) {
        if (recursionStack[vertex]) {
            return INT_MAX;
        }
        if (visited[vertex]) {
            return colorCount[vertex][nodeColors[vertex] - 'a'];
        }
        visited[vertex] = true;
        recursionStack[vertex] = true;

        for (int adjacent : graph[vertex]) {
            if (explore(adjacent, nodeColors, graph, colorCount, visited, recursionStack) == INT_MAX) {
                return INT_MAX;
            }
            for (int color = 0; color < 26; color++) {
                colorCount[vertex][color] = max(colorCount[vertex][color], colorCount[adjacent][color]);
            }
        }

        colorCount[vertex][nodeColors[vertex] - 'a']++;
        recursionStack[vertex] = false;
        return colorCount[vertex][nodeColors[vertex] - 'a'];
    }

    int maximalPathValue(string nodeColors, vector<vector<int>>& edges) {
        int nodes = nodeColors.size();
        vector<vector<int>> graph(nodes);
        for (const auto& edge : edges) {
            graph[edge[0]].push_back(edge[1]);
        }

        vector<vector<int>> colorCount(nodes, vector<int>(26));
        vector<bool> visited(nodes), recursionStack(nodes);
        int maxPathValue = 0;
        for (int v = 0; v < nodes; v++) {
            maxPathValue = max(maxPathValue, explore(v, nodeColors, graph, colorCount, visited, recursionStack));
        }

        return maxPathValue == INT_MAX ? -1 : maxPathValue;
    }
};

The code provided presents a C++ solution designed to determine the largest color value in a directed graph where each vertex has an assigned color. The challenge typically involves detecting cycles in the graph since a cycle may involve infinite loops of color increase, leading to an undefined maximum color value.

  • The explore function serves multiple purposes:

    • It detects cycles using a recursionStack.
    • It carries out depth-first search (DFS) to compute the color counts by propagating maximum color counts from child vertices to parent vertices.
    • It manages both a visited array to keep track of visited nodes and colorCount, a two-dimensional vector that tracks color frequencies at each vertex.
  • The function returns INT_MAX if a cycle is detected, signaling an indefinite maximum value. Otherwise, it computes and returns the maximum count of the current node’s color post DFS traversal.

  • The maximalPathValue function initializes graph structures and loops through each vertex to perform the DFS function calls:

    • It initializes the graph based on given edges, filling the adjacency lists.
    • It initializes other structures necessary for DFS (visited, recursionStack, and colorCount).
    • As it executes DFS from each vertex, it determines the maximum color count obtained from all nodes that were successfully explored (without detecting a cycle).
  • The solution evaluates whether the graph contains cycles affecting any node involved in the maximum color path. If any path resulted in the detection of a cycle (colorCount returns INT_MAX), the function returns -1 to indicate the graph's cyclic nature affecting the result. Otherwise, it outputs the highest color count.

This approach efficiently handles graph-based problems concerning path evaluations and cycle detection, accommodating up to 26 distinct colors represented by characters. The correct usage of DFS and cycle detection in graphs is critical in avoiding infinite loops and ensuring the integrity of the computation. The implementation is robust, catering to various graph structures while ensuring optimal performance with proper handling of edge cases, such as cycle detections.

java
class GraphUtils {
    private int traverse(int node, String paint, Map<Integer, List<Integer>> graph, int[][] tally,
                         boolean[] seen, boolean[] processing) {
        if (processing[node]) return Integer.MAX_VALUE;
        if (seen[node]) return tally[node][paint.charAt(node) - 'a'];
        
        seen[node] = true;
        processing[node] = true;

        if (graph.containsKey(node)) {
            for (int neighbor : graph.get(node)) {
                if (traverse(neighbor, paint, graph, tally, seen, processing) == Integer.MAX_VALUE) {
                    return Integer.MAX_VALUE;
                }
                for (int i = 0; i < 26; i++) {
                    tally[node][i] = Math.max(tally[node][i], tally[neighbor][i]);
                }
            }
        }

        tally[node][paint.charAt(node) - 'a']++;
        processing[node] = false;
        return tally[node][paint.charAt(node) - 'a'];
    }

    public int maxColorValue(String paint, int[][] edges) {
        int n = paint.length();
        Map<Integer, List<Integer>> graph = new HashMap<>();

        for (int[] edge : edges) {
            graph.computeIfAbsent(edge[0], k -> new ArrayList<>()).add(edge[1]);
        }

        int[][] tally = new int[n][26];
        boolean[] seen = new boolean[n];
        boolean[] processing = new boolean[n];
        int maxValue = 0;

        for (int i = 0; i < n; i++) {
            maxValue = Math.max(maxValue, traverse(i, paint, graph, tally, seen, processing));
        }

        return maxValue == Integer.MAX_VALUE ? -1 : maxValue;
    }
}

The provided Java program defines a method to find the largest color value in a directed graph where each node is painted with a color depicted by a character. The program operates in the following manner:

  • Initialization: The maxColorValue method accepts a string, representing the colors of the nodes, and a 2D array of edges defining the directed graph. It prepares the graph map and other helper arrays to keep track of visited nodes, nodes in process, and color frequencies.

  • Graph Construction: For each edge definition in the edges array, the graph's adjacency list is built using a HashMap, where each node points to its neighboring nodes.

  • Cycle Detection & Tallying: The traverse method is recursively called for each node to detect cycles and to tally the count of each color up to that node. Cycle detection is managed using a 'processing' array to check if a node is visited during the current traversal. If a cycle is found (i.e., a node is re-visited before finishing its processing), the function returns Integer.MAX_VALUE.

  • Color Counting: Each node increases the count of its color in the tally for itself after all its neighbors have been traversed. It furthers the maximum count of each color among its neighbors to reflect the longest path that reaches that node.

  • Result Calculation: After iterating over all nodes, the program calculates the maximum value found in the tally arrays, ignoring cases where a cycle was detected (Integer.MAX_VALUE).

  • Output: The maxColorValue function evaluates whether the maximum value is Integer.MAX_VALUE due to a cycle and, if so, returns -1. Otherwise, it returns the maximum color value found, representing the highest frequency of any color along any path in the graph.

This method efficiently handles the complexities of cycle detection and color tallying in directed graphs and provides a robust solution to determine the dominant color based on the paths within the graph.

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