
Problem Statement
In this task, you receive a string ( s ). You are tasked to repeatedly modify the string by performing a defined process that primarily involves choosing a character in the string and removing certain instances of this character based on specific conditions. The process can be carried out an unlimited number of times, with the goal of reducing the length of the string to its minimum possible value through these operations.
Here's a detailed breakdown of the operation:
- You select an index ( i ) in the string. This index must fulfill the condition where the character at index ( i ) (( s[i] )) has at least one identical character somewhere to its left and also to its right within the string.
- Once an appropriate index ( i ) has been chosen, you remove the closest identical character to the left and the closest identical character to the right of ( s[i] ).
The outcome to be determined is the minimal length the string ( s ) can be reduced to, after applying the above operation optimally any number of times.
Examples
Example 1
Input:
s = "abaacbcbb"
Output:
5
Explanation:
* Choose index 2, then remove the characters at indices 0 and 3. The resulting string is `s = "bacbcbb"`. * Choose index 3, then remove the characters at indices 0 and 5. The resulting string is `s = "acbcb"`.
Example 2
Input:
s = "aa"
Output:
2
Explanation:
Constraints
1 <= s.length <= 2 * 105
s
consists only of lowercase English letters.
Approach and Intuition
The goal given the problem is to reduce the string to its minimal length by removing characters according to specified rules. Looking at the examples:
- For
s = "abaacbcbb"
:- The character 'a' at index 2 is selected (s[2] = 'a'). The character 'a' also exists at index 1 to the left and index 3 to the right of index 2. The closest occurrences on both sides are removed, resulting in
s = "bacbcbb"
. - The character 'b' at index 3 is then selected (s[3] = 'b'). It has occurrences at indices 0 to its left and 5 to its right, which are then eliminated. The string further reduces to
s = "acbcb"
.
- The character 'a' at index 2 is selected (s[2] = 'a'). The character 'a' also exists at index 1 to the left and index 3 to the right of index 2. The closest occurrences on both sides are removed, resulting in
- For
s = "aa"
:- There is no valid position where a character has duplicates on both sides that are different from themselves, so no operation can be performed.
Analyzing the constraints and the operations, the task involves several challenges:
- Efficiently identifying valid indices ( i ) for the operation.
- Managing the removal of elements in a way that still allows for quick identification of new valid indices in potentially large-scale strings (up to ( 200,000 ) characters).
- Direct removal from and manipulation of strings isn't efficient in Python due to strings being immutable. Instead, an approach involving data structures that support efficient removal and insertion, like linked lists or using additional arrays to manage active indices of characters, may be required.
The minimum length result is dependent on how effectively the operations are utilized to cluster and remove repeating characters while adhering to the rules provided. An efficient algorithm might thus involve a strategic selection of indices for the operation to maximize removals in each step.
Solutions
- C++
- Java
- Python
class Solution {
public:
int minLen(string str) {
int visible = 0;
int bitMask = 0;
int bitPos;
// Loop over characters to modify bit masks
for (int idx = 0; idx < str.length(); idx++) {
bitPos = 1 << (str[idx] - 'a');
visible |= bitPos;
bitMask ^= bitPos;
}
int minLength = 0;
// Calculate required minimum total length
while (visible) {
bitPos = visible & (visible - 1);
minLength += 2 - ((bitMask & (visible - bitPos)) != 0);
visible = bitPos;
}
return minLength;
}
};
This solution implements a function in C++ to determine the minimum length of a string after applying a series of operations defined by bit manipulation techniques. Here's how the solution works:
- Initialize
visible
andbitMask
to track which characters have been seen and their occurrence counts respectively. - Using a loop, iterate over each character in the input string.
- Calculate
bitPos
, which is a bitmask representing the current character's position in the alphabet. - Update
visible
to include the current character's bitmask. - Use XOR operation on
bitMask
withbitPos
to toggle the character's count between even and odd.
- Calculate
- Initialize
minLength
to zero for calculating the result. - For each character that has been seen (
visible
is not zero):- Determine which characters need to be considered for pairing off by manipulating the bit positions.
- Increase
minLength
by 2 for most characters, except decrease it by 1 if the character has an odd occurrence by checkingbitMask
.
- Finally, return
minLength
which is the calculated minimum length of the string after operations.
Using bit manipulation allows for an efficient mechanism to handle and compute character occurrences leading to the calculation of minimum string length according to given operational rules. This approach ensures a compact and optimal solution, leveraging bitwise operations for fast computation.
class Solution {
public int minStringLength(String input) {
int activeBits = 0;
int flipBits = 0;
int bitMask;
for (int i = 0; i < input.length(); i++) {
bitMask = 1 << (input.charAt(i) - 'a');
activeBits |= bitMask;
flipBits ^= bitMask;
}
int minLength = 0;
while (activeBits > 0) {
bitMask = activeBits & (activeBits - 1);
minLength += 2 - ((flipBits & (activeBits - bitMask)) != 0 ? 1 : 0);
activeBits = bitMask;
}
return minLength;
}
}
The provided Java solution is designed to compute the minimum length of a string after performing specific operations that involve flipping bits to represent characters. The key components and actions in the solution are as follows:
- Initialize variables
activeBits
andflipBits
to keep track of which bits (characters) have been seen and flipped respectively. - Use a bit-wise operation logic that involves a
for
loop iterating over characters in the input string. In each iteration:- Calculate a
bitMask
for the current character to identify its position in the alphabet using a shift operation. - Update
activeBits
using an OR operation onbitMask
to track characters present in the string. - Update
flipBits
using an XOR operation onbitMask
to manage flip states of characters.
- Calculate a
- Determine the minimal length after all characters are processed:
- A while loop is used where the condition checks if there are still active bits.
- In each iteration, update
activeBits
by turning off the rightmost bit, and incrementminLength
based on the condition whether the character was flipped an odd or even number of times. - The expression within incrementing
minLength
uses a bitwise AND and a subtraction to determine if the flipped state should adjust the count by 1 or 2.
Overall, the logic cleverly uses bitwise operations to efficiently calculate the minimal length of the string by accounting for each character's appearance and its number of flips, thus determining how it contributes to the string's final length after all operations are applied. This approach ensures an optimal runtime with a clear focus on bitwise manipulation for string character analysis.
class Solution:
def findMinimumLength(self, str_input: str) -> int:
current_mask = 0
even_odd_mask = 0
single_bit_mask = 0
for character in str_input:
single_bit_mask = 1 << (ord(character) - ord('a'))
current_mask |= single_bit_mask
even_odd_mask ^= single_bit_mask
calculated_length = 0
while current_mask > 0:
single_bit_mask = current_mask & (current_mask - 1)
calculated_length += 2 - ((even_odd_mask & (current_mask - single_bit_mask)) != 0)
current_mask = single_bit_mask
return calculated_length
The Python code provided defines a method within a class that calculates the minimum length of a string after performing certain operations. The method findMinimumLength
uses bit manipulation to efficiently track and process the characters of the input string to determine the resulting length. Here’s a breakdown of how the method works:
- Initialization of Masks: The method begins by initializing three integer variables
current_mask
,even_odd_mask
, andsingle_bit_mask
to keep track of different aspects of the characters in the string. - Character Processing:
- Loop through each character in the input string.
- For each character, calculate a
single_bit_mask
which is based on the character's position in the alphabet (using bitwise shift). - Update
current_mask
with thissingle_bit_mask
using bitwise OR, to record the occurrence of the character. - Update
even_odd_mask
using bitwise XOR to toggle the presence of the character and assist in tracking even and odd occurrences.
- Calculate Minimum Length:
- Initiate
calculated_length
to count the resultant string's length. - Use a while loop to iterate as long as
current_mask
is greater than zero. - In each iteration, adjust
single_bit_mask
to exclude the rightmost 1 bit fromcurrent_mask
. - Increase
calculated_length
based on whether the toggled even-odd occurrence of characters (tracked byeven_odd_mask
) is still one after updatingsingle_bit_mask
. - Update
current_mask
to be the newsingle_bit_mask
for the next iteration.
- Initiate
- Return Calculated Length: After processing all characters and their occurrences, return
calculated_length
, representing the minimum length of the string after performing the operations.
The method meticulously combines bit manipulation techniques to track character occurrences and frequencies efficiently, ensuring an optimal solution to find the minimum length of the processed string.
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