
Problem Statement
In this problem, you are provided with a string s
that comprises only uppercase English letters. Your task is to perform certain operations on this string to minimize its length. The operation you are allowed to perform will enable you to remove any occurrence of the substrings "AB"
or "CD"
from the string. It's important to note that after each removal, the string is concatenated, potentially creating new opportunities to perform additional operations with newly formed "AB"
or "CD"
substrings. Your objective is to determine the minimal possible length of string that can be achieved after performing none, one, or multiple operations.
Examples
Example 1
Input:
s = "ABFCACDB"
Output:
2
Explanation:
We can do the following operations: - Remove the substring "ABFCACDB", so s = "FCACDB". - Remove the substring "FCACDB", so s = "FCAB". - Remove the substring "FCAB", so s = "FC". So the resulting length of the string is 2. It can be shown that it is the minimum length that we can obtain.
Example 2
Input:
s = "ACBBD"
Output:
5
Explanation:
We cannot do any operations on the string so the length remains the same.
Constraints
1 <= s.length <= 100
s
consists only of uppercase English letters.
Approach and Intuition
The key challenge in solving this problem is to effectively find and remove occurrences of "AB"
or "CD"
repeatedly until no further such substrings can be removed. This will involve:
- Examining the string from left to right to find the first occurrence of either "AB" or "CD".
- Once found, these substrings are removed, and the string is concatenated.
- This operation might lead to the creation of new "AB" or "CD" substrings due to the concatenation of the parts of the string before and after the removed substring. Thus, the process needs to be repeated.
- If a pass through the string finds no substrings "AB" or "CD" to remove, the process stops.
- From Example 1 (
"ABFCACDB"
):- The operation sequence is optimal by repeatedly looking for and removing instances of "AB" or "CD" until no more exist, which results in the string "FC", of length 2.
- From Example 2 (
"ACBBD"
):- Since there are no "AB" or "CD" substrings to remove, the minimum length of the string remains as the original length, which is 5.
This approach leverages a greedy strategy, where at every step, removing the first found eligible substring is optimal due to the constraint that only specific substrings can be removed and the potential to form new removable substrings after each operation. The process of scanning and modifying the string is efficiently bounded by the constraints provided (s.length
is at most 100).
Solutions
- C++
class Solution {
public:
int reduceLength(string str) {
int position = 0;
vector<char> temp(str.begin(), str.end());
for (int index = 0; index < str.length(); index++) {
temp[position] = temp[index];
if (position > 0 &&
(temp[position - 1] == 'A' || temp[position - 1] == 'C') &&
temp[position] == temp[position - 1] + 1) {
position--;
} else {
position++;
}
}
return position;
}
};
The provided C++ solution aims to minimize the length of a string by removing certain substrings according to specific rules. The function reduceLength
processes a string by iterating over its characters, leveraging a two-pointer approach (utilizing index
and position
as pointers). Here's a concise breakdown of the approach:
- Initialize
position
to zero. This serves as the effective "current length" of the string being built. - Convert the input string into a vector of characters,
temp
, for efficient modification. - Iterate through the characters of
temp
. During each iteration:- Directly assign the character at
index
totemp[position]
. - Check if the current character can form a consecutive sequence (
A
withB
,B
withC
, etc.) with the previous character. - If such a sequence is detected (
temp[position]
is consecutive totemp[position - 1]
), decrementposition
to effectively remove the last character added. - If no sequence is detected, increment
position
to accept the current character.
- Directly assign the character at
- Return the value of
position
which represents the length of the string after consecutive sequences have been removed.
This solution efficiently removes pairs of consecutive letters, minimizing the length of the string without explicitly deleting elements from the original string, thus maintaining a lower time complexity. The final result after all possible reductions is the length of the new string.
- Java
class Solution {
public int shortestLength(String str) {
int outputIndex = 0;
char[] letters = str.toCharArray();
for (int inputIndex = 0; inputIndex < str.length(); inputIndex++) {
letters[outputIndex] = letters[inputIndex];
if (
outputIndex > 0 &&
(letters[outputIndex - 1] == 'A' ||
letters[outputIndex - 1] == 'C') &&
letters[outputIndex] == letters[outputIndex - 1] + 1
) {
outputIndex--;
} else {
outputIndex++;
}
}
return outputIndex;
}
}
In solving the problem of determining the minimum string length after removing specific substrings, the Java solution involves simulating the process of shortening a given string by selectively omitting certain characters under specific conditions. This method operates by maintaining an output length counter and modifying the string in place.
- Start by converting the input string into a character array for in-place modifications.
- Iterate through the array using a for-loop.
- Assign characters from the input index to the current position of what is tracked by the output index.
- The critical condition checks whether the previous character in the array is 'A' or 'C', and if the current character is directly subsequent to one of these in the ASCII table. If both conditions are met, decrement the output index, effectively removing the character pair from consideration.
- If the condition is not met, simply move the output index forward to consider the next character.
By the end of the loop, outputIndex
reflects the length of the final string after all possible pairs have been removed. This value is then returned as the result. This solution optimizes by working directly on the input string’s character array, ensuring a more efficient and quicker algorithm without needing additional memory for other strings or data structures.
- Python
class Solution:
def filterStringLength(self, input_str: str) -> int:
char_array = list(input_str)
output_index = 0
for current_index in range(len(input_str)):
char_array[output_index] = char_array[current_index]
if (
output_index > 0
and char_array[output_index - 1] in "AC"
and ord(char_array[output_index])
== ord(char_array[output_index - 1]) + 1
):
output_index -= 1
else:
output_index += 1 # No deletion needed, increment the index
return output_index
The provided Python code defines a method filterStringLength
within a Solution
class, aimed at reducing the length of an input string by removing specific substrings. Here's how the method processes the input string:
- It converts the string to a list to manipulate the characters easily.
- The characters are processed one at a time using their positions in the list.
- The function checks for specific characters ('A' and 'C') followed by their immediate successors in the ASCII sequence (i.e., 'B' after 'A' and 'D' after 'C').
- When such sequences are found, the code effectively removes (does not copy) the successor character by not advancing in the output list.
- If no such condition is met, the character from the current position is maintained, and the output index is advanced.
This approach emphasizes an in-place modification of the character array, using output_index
to control the length and content of the final output. The returned output_index
indicates the effective length of the string after all possible removals have happened, reflecting the characters that pass the specified conditions. This method helps in optimizing the length of the string by removing unwanted subsequences, which aligns with string manipulation and optimization tasks in programming.
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