Sum of Digits of String After Convert

class Solution {
public:
    int transformString(string strInput, int iterations) {
        int tempResult = 0;
        for (char c : strInput) {
            int alphaIndex = c - 'a' + 1;
            while (alphaIndex > 0) {
                tempResult += alphaIndex % 10;
                alphaIndex /= 10;
            }
        }

        for (int j = 1; j < iterations; ++j) {
            int sumDigits = 0;
            while (tempResult > 0) {
                sumDigits += tempResult % 10;
                tempResult /= 10;
            }
            tempResult = sumDigits;

            if (tempResult < 10) {
                break;
            }
        }

        return tempResult;
    }
};

This solution in C++ features a function, transformString, designed to sum the digits of string characters after conversion and potentially multiple iterations of summing digits. Here's a concise breakdown of how it works:

1. The function accepts a string strInput and an integer iterations representing the number of times the summing of digits is performed.
2. The string characters are converted to their respective positions in the alphabet (e.g., 'a' = 1, 'b' = 2, etc.).
3. Each character's position value is then added cumulatively after breaking it down into individual digits.
4. After the initial conversion and addition, the result stored in tempResult is then re-evaluated over several iterations (specified by iterations parameter).
5. During each iteration, digits of tempResult are summed up until tempResult is a single-digit number or until all iterations are completed.

• A notable implementation detail is that the function exits early if the resulting tempResult becomes a single-digit number before reaching the maximum specified iterations, optimizing processing time.

This approach meticulously handles the transformation and reduction of digital values through straightforward mathematical manipulations, ensuring efficiency and correctness in obtaining the final sum.

class Solution {

    public int computeLuck(String str, int transformations) {
        int sum = 0;
        for (char c : str.toCharArray()) {
            int val = c - 'a' + 1;
            while (val > 0) {
                sum += val % 10;
                val /= 10;
            }
        }

        for (int j = 1; j < transformations; ++j) {
            int tempSum = 0;
            while (sum > 0) {
                tempSum += sum % 10;
                sum /= 10;
            }
            sum = tempSum;

            if (sum < 10) {
                break;
            }
        }

        return sum;
    }
}

This solution provides a method to compute the resultant sum of digits of a string after converting each character to its respective position in the alphabet and applying transformation reductions. The function, computeLuck, takes two parameters: a string str and an integer transformations indicating how many times the sum should be transformed.

• First, iterate over each character of the string to convert it into a numerical value corresponding to its position in the alphabet ('a' = 1, 'b' = 2, ..., 'z' = 26).

• For each character, convert it to its alphabetical position and compute the sum of its digits.

• Continue to transform the sum for the specified number of transformations:

  • In each transformation, reduce the current sum by summing its individual digits.
  • Check after each transformation if the sum has reduced to a single digit. If it has, exit the loop early as further transformations will not change the sum.

• Finally, return the result, which is a single-digit sum after the specified number of transformations.

This method effectively handles the reduction of numbers to their component digits and can dynamically control the depth of transformation based on input, making it flexible for varied use cases.

class Solution:
    def transformString(self, input_str: str, num_transforms: int) -> int:
        result = 0
        for character in input_str:
            ascii_position = ord(character) - ord('a') + 1
            while ascii_position > 0:
                result += ascii_position % 10
                ascii_position //= 10

        for transform in range(1, num_transforms):
            sum_digits = 0
            while result > 0:
                sum_digits += result % 10
                result //= 10
            result = sum_digits

            if result < 10:
                break

        return result

This Python code defines a class Solution with a method transformString that calculates the sum of the digits of a string after performing several specified transformations. Here’s how the method works:

1. Initialize result to 0 which will hold the cumulative sum.
2. Convert each character in the input string to a number by finding its position in the alphabet (i.e., 'a' = 1, 'b' = 2, ..., 'z' = 26) using the formula ord(character) - ord('a') + 1.
3. For each character’s numeric value, add the sum of its digits to result.
4. After processing all characters in the input string, proceed to transform the resulting number as many times as specified by num_transforms:
   • For each transformation, calculate the sum of the digits of the current result.
   • Update result with this new sum.
   • If result becomes a single digit before reaching the total number of specified transformations, exit the loop early.

The final result, after all transformations are complete or terminated early, is returned as the output of the transformString method.

This approach effectively applies a digit-root-like operation multiple times, which can be useful for tasks that involve digit manipulation and transformation in strings within computational contexts.