
The concept of the power of a string refers to the length of the longest contiguous segment (or substring) within the string that contains exactly one unique character. Given a string s, the task is to calculate its power. This involves identifying the longest substring where the same single character repeats consecutively without any interruption of a different character.
Input:
Output:
Explanation:
Input:
Output:
Explanation:
1 <= s.length <= 500s consists of only lowercase English letters.To solve this problem, we aim to find the maximum length of a substring which is composed entirely of the same character. The approach involves iterating through the string s while maintaining a count of consecutive characters. Here's a step-by-step breakdown:
max_power to store the maximum length of such substrings and current_power to count consecutive characters as you traverse the string.current_power.max_power if current_power is greater, and reset current_power to 1 (since the new different character starts its own potential substring).max_power with current_power one last time.max_power at the end of these steps will be the power of the string.Below are the example walkthroughs based on the given examples:
These insights showcase how to tackle the problem by focusing on consecutive characters and ensure the solution adheres to the constraints that the input string length will not exceed 500 characters, and only lowercase English letters are included.
This code in Java defines a function longestRepetition that determines the length of the longest contiguous block of repeating characters in a given string. The function works as follows:
currentCount and maximumCount, to zero. currentCount keeps track of the current sequence length, and maximumCount stores the maximum sequence length found.lastChar, initialized to a space character, to remember the last character processed.lastChar. If they match, increment currentCount. If not, reset currentCount to 1 and update lastChar to the current character.maximumCount with the larger of maximumCount or currentCount using Math.max.maximumCount after the loop completes, which represents the length of the longest sequence of identical consecutive characters in the string.This function efficiently computes the desired result by making a single pass through the string, maintaining a constant space complexity, and providing an O(n) time complexity, where n is the length of the string.
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