
In this problem, we are working with an infinitely large two-dimensional grid made up of unit cells. Initially, all cells are uncolored. Over a series of n minutes, a coloring process takes place. Here’s how it works:
The goal is to determine the total number of blue colored cells on the grid after n minutes.
Input:
Output:
Explanation:
Input:
Output:
Explanation:
1 <= n <= 105Given the problem's unique way of coloring cells across minutes, we can derive the pattern of cell expansion:
Given a cell selected randomly at the beginning, the growth of the colored area can be visualized as follows:
The number of blue cells can thus be calculated using the growth pattern:
n minutes is n - 1 cells away in the cardinal directions.n minutes is 2n^2 - 2n + 1. This formula comes from observing that the expansion forms concentric diamonds of increasing size, where each side of the diamond i layers away from the center is 2i cells plus the center cell.Understanding these points helps in visualizing and solving the problem efficiently without the need for simulating the process on an actual grid, thus optimizing for larger values of n within computational constraints.
The provided C++ solution comprises a class named Solution responsible for counting the total number of colored cells. The function countColoredCells(int m) calculates the total number of colored cells in a grid, utilizing the formula 1 + (long long)m * (m - 1) * 2. This formula strategically uses mathematical operations to derive the result based on the input value of m. The method correctly returns a long long type output, ensuring that it can handle large numbers that might result from large inputs for m. This solution is efficient as it computes the result in constant time, O(1), given that it uses only arithmetic calculations without any loops or recursion.
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