
Problem Statement
In this problem, you are provided with an array cookies
, each element of which represents the number of cookies in a specific bag. Additionally, a number k
signifies the total children available for distribution of these bags. The critical rule here is that cookies from the same bag must go entirely to a single child and cannot be divided among multiple children.
The goal is to distribute these bags among the k
children such that the unfairness of the distribution is minimized. Unfairness is defined as the highest total number of cookies received by any single child from their allocated bags. Thus, the solution requires finding a distribution where the maximum cookies any child receives is the smallest possible when compared to all other feasible distributions.
Examples
Example 1
Input:
cookies = [8,15,10,20,8], k = 2
Output:
31
Explanation:
One optimal distribution is [8,15,8] and [10,20] - The 1st child receives [8,15,8] which has a total of 8 + 15 + 8 = 31 cookies. - The 2nd child receives [10,20] which has a total of 10 + 20 = 30 cookies. The unfairness of the distribution is max(31,30) = 31. It can be shown that there is no distribution with an unfairness less than 31.
Example 2
Input:
cookies = [6,1,3,2,2,4,1,2], k = 3
Output:
7
Explanation:
One optimal distribution is [6,1], [3,2,2], and [4,1,2] - The 1st child receives [6,1] which has a total of 6 + 1 = 7 cookies. - The 2nd child receives [3,2,2] which has a total of 3 + 2 + 2 = 7 cookies. - The 3rd child receives [4,1,2] which has a total of 4 + 1 + 2 = 7 cookies. The unfairness of the distribution is max(7,7,7) = 7. It can be shown that there is no distribution with an unfairness less than 7.
Constraints
2 <= cookies.length <= 8
1 <= cookies[i] <= 105
2 <= k <= cookies.length
Approach and Intuition
Based on the examples provided and the constraints, the concept behind solving the problem can be outlined as follows:
The core challenge is to distribute the bags in such a way that the child who gets the maximum cookies receives as few as possible, compared to other distributions.
Given the constraints:
- The maximum length for
cookies
is 8, meaning the problem size is relatively small, which hints that computational heavy operations like permutations or combinations might be feasible. - The constraints on the values within
cookies
([1, 105]) establish that straight calculations on these during permutations won’t cause computational overhead.
- The maximum length for
From the examples:
- Example 1 gives
cookies = [8,15,10,20,8]
andk = 2
. An optimal grouping here turned out to be[8,15,8]
and[10,20]
, resulting in a maximum of 31 cookies to one child. This instructively shows a split where a balance is somewhat maintained between groups despite one group having more bags. - Example 2 illustrates a case with more bags and one additional child (
k = 3
). The optimal distribution evenly splits the total cookies, hence achieving an outright balance across all groups.
- Example 1 gives
The problem likely requires examining all possible distributions of the cookie bags to calculate the maximum cookies a child receives in each scenario, and then selecting the distribution where this maximum is the lowest.
Systematically, this can be approached by:
- Generating all possible ways to distribute the
n
bags amongstk
kids where each kid must get at least one bag. - For each distribution, compute the sum of cookies each kid would receive.
- Record the maximum cookies received by any kid for each distribution.
- The desired minimum unfairness would thus be the smallest of these recorded maximums.
- Generating all possible ways to distribute the
In conclusion, tackling the unfairness minimization involves exploring combinations of how bags can be distributed among kids, each time calculating and then minimizing the cookies received by the most favored child in terms of cookie count. A suitable algorithm might involve recursive function calls with memorization to efficiently navigate through possible distributions.
Solutions
- C++
- Java
- Python
class Solution {
public:
int recursiveDistribute(int idx, vector<int>& kids, vector<int>& sweets, int numKids, int zeroKids) {
if (sweets.size() - idx < zeroKids) {
return INT_MAX;
}
if (idx == sweets.size()) {
return *max_element(kids.begin(), kids.end());
}
int minUnfairness = INT_MAX;
for (int j = 0; j < numKids; ++j) {
zeroKids -= kids[j] == 0 ? 1 : 0;
kids[j] += sweets[idx];
minUnfairness = min(minUnfairness, recursiveDistribute(idx + 1, kids, sweets, numKids, zeroKids));
kids[j] -= sweets[idx];
zeroKids += kids[j] == 0 ? 1 : 0;
}
return minUnfairness;
}
int distributeSweets(vector<int>& sweets, int numKids) {
vector<int> kids(numKids, 0);
return recursiveDistribute(0, kids, sweets, numKids, numKids);
}
};
The provided C++ solution revolves around solving the problem of fair distribution of cookies to a certain number of kids. The key objective is to minimize the maximum number of cookies any kid receives, ensuring as fair a distribution as possible. The solution employs a recursive depth-first search (DFS) approach to distribute the cookies.
The
distributeSweets
function serves as the main entry point, initializing each kid's cookie count to zero and callingrecursiveDistribute
.The
recursiveDistribute
function uses recursion to explore every possible way of distributing the cookies.- It terminates returning an infinitely large value if there are not enough cookies left to ensure each remaining kid gets at least one.
- It returns the maximum cookies held by any kid when all cookies are successfully distributed, marking the base case of the recursion.
- For each cookie, the function attempts to distribute it to every kid and recursively call itself to handle the next cookie, updating the minimum observed unfair distribution at each step.
An important aspect is ensuring that the distribution continues to track scenarios where any kid has yet to receive a cookie (managed by
zeroKids
counter), helping to optimize the recursive distribution by avoiding meaningless recursion paths where not every kid can get a cookie.
The solution heavily relies on efficiently managing recursive state transitions as cookies are distributed among kids and backtracking where necessary, ensuring it explores optimal and feasible distributions given the constraints. The complexity of the approach can grow substantially with increasing numbers of kids and cookies due to the combinatorial nature of the problem.
class Distribution {
private int partition(int index, int[] childCookies, int[] cookies, int children, int countZeros) {
if (cookies.length - index < countZeros) {
return Integer.MAX_VALUE;
}
if (index == cookies.length) {
int worstCase = Integer.MIN_VALUE;
for (int amt : childCookies) {
worstCase = Math.max(worstCase, amt);
}
return worstCase;
}
int minimumUnfairness = Integer.MAX_VALUE;
for (int j = 0; j < children; ++j) {
countZeros -= childCookies[j] == 0 ? 1 : 0;
childCookies[j] += cookies[index];
minimumUnfairness = Math.min(minimumUnfairness, partition(index + 1, childCookies, cookies, children, countZeros));
childCookies[j] -= cookies[index];
countZeros += childCookies[j] == 0 ? 1 : 0;
}
return minimumUnfairness;
}
public int distributeSnacks(int[] cookies, int children) {
int[] childCookies = new int[children];
return partition(0, childCookies, cookies, children, children);
}
}
The provided Java code aims to evenly distribute cookies among children to minimize the maximum amount of cookies any single child receives, thus ensuring fairness. The Distribution
class includes methods that work collaboratively to achieve this distribution through a recursive partitioning approach.
- The
distributeSnacks
function prepares for the recursive partitioning by initializing an arraychildCookies
to store the distribution of cookies for each child and then calls thepartition
function. - The
partition
function is a recursive function designed to distribute the cookies. It attempts various distributions by giving each child one cookie from the remaining cookies and recursively solving the smaller problem. - The base case for the recursion occurs when all cookies have been considered (
index == cookies.length
). At this point, the function calculates and returns the maximum number of cookies any child has received, representing the "worst case" unfairness scenario. - As the function iterates through different cookie distributions, it tracks the minimum value of the maximum cookies any child receives using
minimumUnfairness
, updating it each time a more fair distribution is found. - The function also carefully manages scenarios with initially zero cookies using the
countZeros
parameter, ensuring that the logic handles cases where all children start with no cookies.
Ultimately, distributeSnacks
returns the least unfair distribution of cookies among the children, ensuring that the difference between the largest and smallest number of cookies any child receives is as small as possible. This solution approach effectively uses recursion and backtracking to explore different distributions and find the optimal way to ensure fairness in cookie distribution.
class Distributor:
def allocateCookies(self, sweets: List[int], children: int) -> int:
child_sweets = [0] * children
total_sweets = len(sweets)
def recurse(index, zero_counter):
if total_sweets - index < zero_counter:
return float('inf')
if index == total_sweets:
return max(child_sweets)
min_disparity = float('inf')
for child in range(children):
zero_counter -= int(child_sweets[child] == 0)
child_sweets[child] += sweets[index]
min_disparity = min(min_disparity, recurse(index + 1, zero_counter))
child_sweets[child] -= sweets[index]
zero_counter += int(child_sweets[child] == 0)
return min_disparity
return recurse(0, children)
The Fair Distribution of Cookies problem seeks to allocate a list of cookies among a specific number of children in a manner that minimizes the maximum number of cookies any child receives, aiming for an even distribution.
The Python implementation involves defining a class Distributor
with the method allocateCookies
, which takes two parameters: sweets
, a list of integers representing the cookies, and children
, the number of children. The solution leverages a recursive approach to explore all possible distributions and determines the one with the minimum disparity in cookie allocation among the children.
Initialization: An array
child_sweets
initialized to zero is created to track the number of sweets each child receives. A variabletotal_sweets
stores the number of different sweets available.Recursive Function: The inner function
recurse
is defined with parametersindex
andzero_counter
, which keep track of the current sweet being distributed and the number of children who have received no sweets so far, respectively.The base case checks if it's possible to distribute the remaining sweets; if not, it returns infinity to indicate an invalid distribution. If all sweets are accounted for, it returns the maximum number of sweets any child has.
The recursive step involves iterating through each child, attempting to add the current sweet to each child's total one at a time, then recursively calling itself with the next index. It then backtracks by removing the sweet just added—a depth-first search approach to explore all possible distributions.
During this process, a
min_disparity
variable captures the smallest maximum number of sweets any child has across all complete explorations of sweet distribution paths.
Final Calculation: The
allocateCookies
method initiates the recursion starting from the first sweet and all children having received no sweets, and returns the minimum possible maximum number of sweets among children, given a fair distribution.
This approach ensures that every potential way of distributing cookies is considered, though it may become computationally intensive with a large number of cookies or children due to its exhaustive nature.
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