Maximum Ascending Subarray Sum

class Solution {
public:
    int findMaxAscendingSum(vector<int>& arr) {
        int highestSum = 0;
        int tempSum = arr[0];
        
        for (int i = 1; i < arr.size(); ++i) {
            if (arr[i] <= arr[i - 1]) {
                highestSum = max(highestSum, tempSum);
                tempSum = 0;
            }
            tempSum += arr[i];
        }
        
        return max(highestSum, tempSum);
    }
};

To solve the problem of finding the Maximum Ascending Subarray Sum using C++, the provided solution utilizes a simple yet effective iterative approach to traverse the array while keeping track of sum accumulations for ascending sequences.

• Start by initializing two integer variables: highestSum to hold the maximum sum found and tempSum to store the current sum, starting with the first element of the array.
• Traverse the array starting from the second element. For each element:
  • Compare the current element with the previous one.
  • If the current element is less than or equal to the previous, update highestSum with the maximum of highestSum and tempSum, and reset tempSum to zero since the ascending sequence has ended.
  • Regardless of the condition, always add the current element's value to tempSum.
• After the loop concludes, compare highestSum with tempSum one last time to ensure no ascending sequence at the end of the array is missed.
• Return highestSum, which now holds the maximum sum of an ascending subarray in the provided array.

Consider implementing these steps to efficiently find the maximum sum of any ascending subarray within a given list of integers. With its rudimentary control structure and effective use of conditional checks and updates, this C++ solution elegantly addresses the problem without the need for complex data structures.

public class Solution {

    public int findMaxAscendingSum(int[] values) {
        int highestSum = 0;
        int sumOfSubarray = values[0];

        for (int i = 1; i < values.length; ++i) {
            if (values[i] <= values[i - 1]) {
                highestSum = Math.max(highestSum, sumOfSubarray);
                sumOfSubarray = 0;
            }
            sumOfSubarray += values[i];
        }

        return Math.max(highestSum, sumOfSubarray);
    }
}

The code in Java defines a method findMaxAscendingSum which calculates the maximum sum of any continuously ascending subarray within the given array values. Below highlights the approach taken within the method:

1. Initialize highestSum to store the maximum sum encountered during the iteration through the array.
2. Start by setting sumOfSubarray with the first element of the array, as this will begin the process of iterating and summing potential ascending sequences.

Continue iterating through the array from the second element using the following mechanism:

• Check if the current element is greater than the previous element to determine if the sequence is still ascending.
• If the sequence breaks (current element is less than or equal to the previous one), compare sumOfSubarray with highestSum and update highestSum if sumOfSubarray is greater.
• Reset sumOfSubarray for a new potential ascending sequence starting from the current element.
• If the sequence has not broken, simply add the current element’s value to sumOfSubarray.

After completing the loop, ensure to check one last time if the last counted sumOfSubarray is the highest sum found during the iteration.

This method ensures that all possible ascending sequences within the array are considered and that the highest sum of such sequences is efficiently found and returned.

class Solution:
    def findMaxAscendingSum(self, data: List[int]) -> int:
        highestSum = 0
        sumOfSubarray = data[0]

        for index in range(1, len(data)):
            if data[index] > data[index - 1]:
                sumOfSubarray += data[index]
            else:
                highestSum = max(highestSum, sumOfSubarray)
                sumOfSubarray = data[index]

        return max(highestSum, sumOfSubarray)

This code defines a method findMaxAscendingSum within the Solution class that computes the maximum sum of an ascending subarray within a given list of integers. Follow the steps below to understand the implementation in detail:

1. Initialize highestSum to 0 to track the highest ascending subarray sum.
2. Start the sumOfSubarray with the first element in the list as this will be used to accumulate the sum of the current ascending subarray.
3. Iterate over the list starting from the second element. Use an index to help track positions in the list:
   • If the current element is greater than the previous element, it means the sequence is still ascending. Thus, add the current element to sumOfSubarray.
   • Otherwise, update highestSum with the greater of highestSum or sumOfSubarray then reset sumOfSubarray to the current element, as the sequence has broken.
4. After the loop, there might be an ongoing ascending subarray not yet considered in highestSum. Resolve this by taking the maximum of highestSum and sumOfSubarray one last time.
5. Return highestSum as the maximum sum of an ascending subarray found.

Use this method to identify the maximum sum of any contiguous ascending subarray within a list of numbers, thereby optimizing the processing of sequential data analysis tasks.