Maximum Score After Splitting a String

class Solution {
public:
    int highestScore(string str) {
        int countOnes = 0;
        int countZeros = 0;
        int maxScore = INT_MIN;

        for (int i = 0; i < str.length() - 1; i++) {
            if (str[i] == '1') {
                countOnes++;
            } else {
                countZeros++;
            }
            
            maxScore = max(maxScore, countZeros - countOnes);
        }
        
        if (str[str.length() - 1] == '1') {
            countOnes++;
        }
        
        return maxScore + countOnes;
    }
};

The problem presented aims to find the maximum score obtained by splitting a given string into two non-empty parts where the score is calculated based on the number of 0s in the left part and the number of 1s in the right part. The approach used in the C++ solution involves iterating through the string, updating counts of 0s and 1s, and keeping track of the maximum score as the string is processed.

Here's an outline of how the code accomplishes this:

• Initialize counters for 1s (countOnes) and 0s (countZeros) and a variable to hold the maximum score (maxScore), setting it to INT_MIN initially.
• Iterate through the string until the second last character.
  • Increase the countOnes if the current character is 1.
  • Increase the countZeros if the current character is 0.
  • Update maxScore using the difference between countZeros and countOnes.
• After exiting the loop, check and increment the countOnes if the last character of the string is 1.
• Return the final score calculated by adding countOnes to maxScore.

This method ensures that the solution is efficient and handles the string manipulation in a linear pass, calculating the maximum possible score optimally.

class Solution {
    public int calculateMaxScore(String str) {
        int countOnes = 0;
        int countZeros = 0;
        int maxScore = Integer.MIN_VALUE;
        
        for (int idx = 0; idx < str.length() - 1; idx++) {
            if (str.charAt(idx) == '1') {
                countOnes++;
            } else {
                countZeros++;
            }
            
            maxScore = Math.max(maxScore, countZeros - countOnes);
        }
        
        if (str.charAt(str.length() - 1) == '1') {
            countOnes++;
        }
        
        return maxScore + countOnes;
    }
}

Maximizing the score after splitting a string involves a combination of counting and optimization strategies. This Java solution defines a function calculateMaxScore that takes a string of zeros and ones as input and determines the maximum score possible by splitting the string into two parts.

• Start by initializing three integer variables countOnes, countZeros, and maxScore. countOnes and countZeros keep track of the number of '1's and '0's respectively in the first part of the string split, and maxScore, initially set to Integer.MIN_VALUE, stores the maximum calculated score so far.
• Loop through all possible split positions in the string, except for the last character, using a for loop. For each index idx:
  • If str.charAt(idx) is '1', increment countOnes; otherwise, increment countZeros.
  • Update maxScore to be the greater value between the current maxScore and (countZeros - countOnes). Here, (countZeros - countOnes) effectively calculates the score at the current split position.
• After the loop, conditionally increase countOnes if the last character of the string is '1'.
• Finally, return maxScore + countOnes. The addition of countOnes accounts for all the '1's counted that contribute positively to the score after the final split, ensuring the result includes contributions from all parts of the string.

Through this logical strategy, the function efficiently computes the maximum score by leveraging differences in the counts of '1's and '0's at every possible split, providing a solution optimal for scenarios where such string characteristics determine outcomes.

class Solution:
    def calculateMaxScore(self, input_string: str) -> int:
        count_ones = 0
        count_zeros = 0
        maximum_score = -float('inf')

        for index in range(len(input_string) - 1):
            if input_string[index] == "1":
                count_ones += 1
            else:
                count_zeros += 1
            
            maximum_score = max(maximum_score, count_zeros - count_ones)
            
        if input_string[-1] == "1":
            count_ones += 1
        
        return maximum_score + count_ones

In the "Maximum Score After Splitting a String" task, your goal is to identify the maximum score achievable by splitting a binary string. This Python3 solution involves iterating through the string (except the last character) to calculate a score by tracking the number of zeroes and ones. Each position in the string where a split could be made is evaluated to determine its contribution to the score using the formula count_zeros - count_ones. The maximum score is continually updated while iterating through the string.

Here's a breakdown of the approach taken:

• Initialize counters for ones (count_ones) and zeros (count_zeros) and set the maximum_score to negative infinity to ensure that it will be updated with any valid score during the initial comparison.
• Iterate over the string except the last character, updating the counts of ones and zeros and subsequently updating the maximum_score based on the difference between the counts of zeros and ones up to that point.
• After the loop, account for the last character by updating the count of ones if needed.
• The final score gets computed by adding count_ones to maximum_score, accounting for the influence of all ones in the string.

This method efficiently evaluates potential splits by leveraging the difference in occurrence of '1's and '0's up to each character in the string, enabling the determination of the best point to split the string for maximizing the score.