Richest Customer Wealth

class Solution {
public:
    int richestCustomerWealth(vector<vector<int>>& customerAccounts) {
        int wealthiest = 0;
        for (auto& account : customerAccounts) {
            int totalWealth = 0;
            for (int balance : account) {
                totalWealth += balance;
            }
            wealthiest = max(wealthiest, totalWealth);
        }
        return wealthiest;
    }
};

The provided C++ solution aims to identify the maximum wealth owned by a customer from a list of customer account balances, where each customer's wealth is the sum of all the balances in their account. Using the standard vector container from the C++ Standard Library, the solution processes a 2D vector where each sub-vector represents the balance accounts of an individual customer.

Here's an overview of how the solution works:

• The function richestCustomerWealth takes a 2D vector customerAccounts as its parameter, which holds the information of multiple customers' account balances.
• The variable wealthiest is initialized to zero, serving as a tracker for the highest wealth found.
• A nested loop structure is used to iterate through customerAccounts:
  • The outer loop traverses each customer's list of account balances.
  • The inner loop sums up all the integers in the current customer's account list to compute their total wealth.
  • The wealthiest variable is updated using the max function to ensure it holds the highest wealth observed at any point in the iterations.
• After processing all customer data, the function returns the wealthiest variable, which contains the maximum wealth among all customers.

This approach efficiently computes the richest customer's wealth by summing up individual account balances and continuously checking if the current total exceeds the recorded maximum. The utilization of the max function ensures optimal comparison and updating of the wealthiest account during each iteration.

class Solution {
    public int findGreatestWealth(int[][] accounts) {
        int greatestWealth = 0;
            
        for (int[] customer : accounts) {
            int totalWealth = 0;
            for (int bank : customer) {
                totalWealth += bank;
            }
            greatestWealth = Math.max(greatestWealth, totalWealth);
        }
            
        return greatestWealth;
    }
}

The problem "Richest Customer Wealth" involves calculating the maximum wealth a customer can have. Wealth is defined as the sum of money in all bank accounts a customer has. The provided Java solution to this problem uses a nested loop structure to achieve this calculation.

Here's an overview of how the Java code solves the problem:

• Initialize greatestWealth to zero to keep track of the highest wealth found.
• Iterate through each customer's array of accounts. For each customer:
  • Initialize totalWealth to zero for summing the individual account balances.
  • Iterate through the accounts and add each balance to totalWealth for the current customer.
  • After processing all accounts for a customer, compare totalWealth with greatestWealth. If totalWealth is greater, update greatestWealth.
• The value of greatestWealth after examining all customers is the desired maximum wealth.

The usage of Math.max ensures that the greatest wealth is always tracked accurately, and the inner loop sums up each customer’s wealth efficiently, making the code straightforward to follow. This solution effectively handles the given data structure int[][] accounts, where each row represents a different customer and each column represents different bank accounts. The final result is the maximum wealth found among all customers.

class Solution:
    def findMaxWealth(self, accounts: List[List[int]]) -> int:
        highest_wealth = 0
            
        for customer_accounts in accounts:
            wealth = sum(customer_accounts)
            highest_wealth = max(highest_wealth, wealth)
                
        return highest_wealth

The provided Python 3 solution efficiently calculates the richest customer wealth from a list of lists representing each customer's account balances. Each inner list contains integers indicating the amount of money in each account. The function findMaxWealth initializes a variable highest_wealth to zero and iterates over each customer's accounts. During each iteration, it calculates the sum of the current customer's accounts and updates highest_wealth if this sum is greater than the current highest_wealth. The final value after completing the iterations over all accounts is the maximum wealth found among all customers. This approach ensures a direct and efficient computation of the problem, leveraging basic Python list operations and functions like sum() and max().