
In this problem, a robot initiates its movement from the origin, coordinate (0,0), on a two-dimensional plane. Throughout its journey, it follows a sequence of steps predefined in the string moves, where each character indicates a specific direction ('L' for left, 'R' for right, 'U' for up, and 'D' for down). The challenge is to determine if, after executing all the moves in the sequence, the robot returns exactly to its starting point at the origin. The function should return true if the robot does return to (0, 0), and false otherwise. Each move is of uniform magnitude, and the orientation or 'facing direction' of the robot is not necessary for the computation of its final position.
Input:
Output:
Explanation:
Input:
Output:
Explanation:
1 <= moves.length <= 2 * 104moves only contains the characters 'U', 'D', 'L' and 'R'.When considering how to determine if the robot returns to the origin, it becomes apparent that each move can either cancel out another move or contribute to a net displacement from the origin:
Each 'R' (right) and 'L' (left) move impacts the robot's x-coordinate.
Each 'U' (up) and 'D' (down) move impacts the robot's y-coordinate.
To determine if the robot returns to the origin:
true. If either condition fails, the function should return false.This logic effectively checks for a balance in horizontal and vertical movements, ensuring that any movement away from the origin in any direction is matched by an equivalent movement back towards the origin.
The Java solution provided determines if a robot, after moving through a series of commands, returns to its original starting position. The commands for movement are represented by the string "path", where each character ('U', 'D', 'L', 'R') corresponds to a direction (Up, Down, Left, Right).
horizontal and vertical, to track the robot's position along the x-axis and y-axis.path into a character array and iterate over it using a for-each loop.horizontal or vertical counters based on the current direction:vertical count (move up).vertical count (move down).horizontal count (move left).horizontal count (move right).horizontal and vertical are zero. If true, the robot has returned to the origin.Return true if the robot returns to the origin; otherwise, return false. This solution operates in O(n) time complexity, where n is the length of the path, as it requires a single scan of the input string to evaluate the robot's final position.
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