
You are given a grid of size m x n, where each cell in the grid is one of four types:
1 – The starting square (exactly one exists).2 – The ending square (exactly one exists).0 – An empty square that can be walked over.-1 – An obstacle that cannot be visited.Your task is to determine how many unique paths exist from the starting square to the ending square such that:
Input:
Output:
Explanation:
Input:
Output:
Explanation:
Input:
Output:
Explanation:
m == grid.lengthn == grid[i].length1 <= m, n <= 201 <= m * n <= 20-1 <= grid[i][j] <= 21 (start) and one is 2 (end)To solve this, we can use recursive backtracking (DFS) with the goal of visiting each empty square exactly once and reaching the ending square.
Preprocessing:
0) that need to be visited.1).Recursive DFS Traversal:
From the starting square, explore all 4 possible directions.
For each move:
If the current cell is the ending square:
Backtracking:
Return the Total Count:
Since the total number of cells is constrained to at most 20, this backtracking-based exhaustive search is efficient. The small size allows us to try all permutations of traversable paths without performance concerns.
The given Java solution resolves the "Unique Paths III" problem by finding all unique paths from a start point to an endpoint on a grid while traversing all non-obstacle spaces exactly once. Below is a summary of how the solution is implemented:
Define global variables for grid dimensions (rLen and cLen), the grid itself (matrix), and to keep track of the total number of paths (totalPaths).
Implement a recursive helper function searchPaths:
totalPaths if the end cell (2) is reached and all cells (sans obstacles) have been visited.-4 and adjust the count of remaining cells.deltasR and deltasC).The uniquePathsIII method:
matrix) and global variables. searchPaths method from the start coordinates with the total number of free spaces as the parameter to track the number of cells left to visit.This method efficiently explores all possible paths using backtracking, ensuring each valid path is counted once all constraints are satisfied. The recursive nature paired with careful state management (marking and unmarking visited cells) allows the solution to avoid revisiting configurations that have already been explored, ensuring optimal performance for larger grids.
The provided Python code defines a class Explorer which includes a method countUniquePaths used to find all unique paths from a starting point to an endpoint in a grid, traversing every non-blocked cell exactly once. The grid cells can be free, blocked, a starting entry, or a destination and are represented as integers (0 for open, -1 for blocked, 1 for start, and 2 for end).
backtrack is defined within countUniquePaths to handle the path exploration, altering its behavior based on the current cell's value and the remaining number of cells to visit.This approach guarantees that all potential paths are explored while maintaining an efficient traversal of the grid by skipping over non-viable paths early. The usage of recursion and backtracking makes it a fit for smaller grids where paths are computationally feasible to enumerate.
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